Answer
See below.
Work Step by Step
$LHS=\frac{sin(u)/cos(u)-cos(u)/sin(u)}{sin(u)/cos(u)+cos(u)/sin(u)}+1=\frac{sin^2(u)-cos^2(u)}{sin^2(u)+cos^2(u)}+1=sin^2(u)-cos^2(u)+1=2sin^2(u)=RHS$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 7 - Analytic Trigonometry - 7.4 Trigonometric Identities - 7.4 Assess Your Understanding - Page 476: 65
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