Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - 7.4 Trigonometric Identities - 7.4 Assess Your Understanding - Page 476: 71

Answer

See explanations.

Work Step by Step

$LHS=\frac{1/cos\theta-1/sin\theta}{(1/cos\theta)(1/sin\theta)}\times\frac{sin\theta cos\theta}{sin\theta cos\theta}=sin\theta-cos\theta=RHS$
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