Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - 7.4 Trigonometric Identities - 7.4 Assess Your Understanding - Page 476: 49

Answer

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Work Step by Step

Divide the left side numerator and denominator by $sin\theta$ and use the relation $csc\theta=\frac{1}{sin\theta}$. We have $LHS=\frac{1/sin\theta+1}{1/sin\theta-1}=\frac{csc\theta+1}{csc\theta-1}=RHS$
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