Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - 7.4 Trigonometric Identities - 7.4 Assess Your Understanding - Page 476: 50

Answer

See explanations.

Work Step by Step

Divide the left side numerator and denominator by $cos\theta$ and use the relation $sec\theta=\frac{1}{cos\theta}$. We have $LHS=\frac{1+1/cos\theta}{1-1/cos\theta}=\frac{1+sec\theta}{1-sec\theta}=RHS$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.