Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - 7.4 Trigonometric Identities - 7.4 Assess Your Understanding - Page 476: 55

Answer

See explanations.

Work Step by Step

$LHS=\frac{1-sin\theta}{1+sin\theta}\times\frac{1-sin\theta}{1-sin\theta}=\frac{(1-sin\theta)^2}{1-sin^2\theta}=\frac{(1-sin\theta)^2}{cos^2\theta}=(\frac{1}{cos\theta}-\frac{sin\theta}{cos\theta})^2=(sec\theta-tan\theta)^2=RHS$
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