Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - 7.4 Trigonometric Identities - 7.4 Assess Your Understanding - Page 476: 70

Answer

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Work Step by Step

$LHS=\frac{1-cot^2\theta}{csc^2\theta}+2cos^2\theta=(1-cos^2\theta/sin^2\theta)sin^2\theta+2cos^2\theta=sin^2\theta-cos^2\theta+2cos^2\theta=1=RHS$
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