Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - 7.4 Trigonometric Identities - 7.4 Assess Your Understanding - Page 476: 66

Answer

See explanations.

Work Step by Step

$LHS=\frac{tan(u)-cot(u)}{tan(u)+cot(u)}\times\frac{cot(u)}{cot(u)}+2cos^2(u)=\frac{1-cot^2(u)}{1+cot^2(u)}+2cos^2(u)=\frac{1-cos^2(u)/sin^2(u)}{csc^2(u)}+2cos^2(u)=sin^2(u)-cos^2(u)+2cos^2(u)=sin^2(u)+cos^2(u)=1=RHS$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.