Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - 7.4 Trigonometric Identities - 7.4 Assess Your Understanding - Page 476: 27

Answer

See explanations.

Work Step by Step

$LHS=tan(u)cot(u)-cos^2(u)=\frac{sin(u)}{cos(u)}\cdot \frac{cos(u)}{sin(u)}-cos^2(u)=1-cos^2(u)=sin^2(u)=RHS$
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