Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - 7.4 Trigonometric Identities - 7.4 Assess Your Understanding - Page 476: 54

Answer

See explanations.

Work Step by Step

$LHS=\frac{1+cos\theta-sin^2\theta}{1+cos\theta}=\frac{cos\theta+cos^2\theta}{1+cos\theta}=\frac{cos\theta(1+cos\theta)}{1+cos\theta}=cos\theta=RHS$
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