Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - 7.4 Trigonometric Identities - 7.4 Assess Your Understanding - Page 476: 45

Answer

See explanations.

Work Step by Step

Divide the left side numerator and the denominator by $tan(v)$ and use the relation $cot(v)=\frac{1}{tan(v)}$. We have $LHS=\frac{\frac{1}{tan(v)}+1}{\frac{1}{tan(v)}-1}=\frac{cot(v)+1}{cot(v)-1}=RHS$
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