Precalculus (10th Edition)

Published by Pearson

Chapter 7 - Analytic Trigonometry - 7.4 Trigonometric Identities - 7.4 Assess Your Understanding - Page 476: 21

Proven below.

Work Step by Step

The identity says: $cot(\theta)=\frac{cos\theta}{sin\theta}$ and $csc(\theta)=\frac{1}{sin(\theta)}$. Hence $cos(\theta)\cdot csc(\theta)=cos(\theta)\cdot \frac{1}{sin(\theta)}=\frac{cos(\theta)}{sin\theta}=cot\theta.$

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