Answer
See image:
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Work Step by Step
Divide the equation with 2304
$ \displaystyle \frac{x^{2}}{36}-\frac{y^{2}}{64}=1,\ \quad$
We recognize the standard equation of a hyperbola.
The foci are on the x-axis:
$\quad \displaystyle \frac{x^{2}}{a^{2}}-\frac{y^{2}}{b^{2}}=1\quad a=6, \ b=8$
Center-to-focus distance: $\quad c=\sqrt{a^{2}+b^{2}}=\sqrt{36+64}=10$
Foci: $\quad (\pm c, 0)=\quad (\pm 10, 0)$
Vertices: $\quad (\pm a, 0)=\quad (\pm 6, 0)$
Asymptotes: $\quad y=\displaystyle \pm\frac{b}{a}x=\pm\frac{8}{6}x$
$y=\displaystyle \pm\frac{4}{3}x$
