Chapter 11: Parametric Equations and Polar Coordinates - Section 11.6 - Conic Sections - Exercises 11.6 - Page 678: 16

Focus: $(\displaystyle \frac{1}{8},0)\quad$ Directrix: $x=-\displaystyle \frac{1}{8}$ .

$x=2y^{2}$ $y^{2}=(\displaystyle \frac{1}{2})x$ $ y^{2}=4px \quad \Rightarrow \quad$ the parabola opens right, $y^{2}=4(\displaystyle \frac{1}{2\cdot 4})x$ $y^{2}=4(\displaystyle \frac{1}{8})x\quad \Rightarrow \quad p=\frac{1}{8}$ Focus: $(\displaystyle \frac{1}{8},0)\quad$ Directrix: $x=-\displaystyle \frac{1}{8}$