Answer
See image:
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Work Step by Step
Divide the equation with $112$
$\displaystyle \frac{x^{2}}{16}+\frac{y^{2}}{7}=1$
$\displaystyle \frac{x^{2}}{4}+\frac{y^{2}}{(\sqrt{7})^{2}}=1$, which is of the form $\quad \displaystyle \frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1 \quad (a\gt b)$,
$\Rightarrow$ the foci are on the x-axis.
Center-to-focus distance: $\quad c=\sqrt{a^{2}-b^{2}}=\sqrt{16-7}=3$
Foci: $\quad(\pm c, 0)= \quad(\pm 3, 0)$
Vertices: $\quad (\pm a, 0)= \quad (\pm 4, 0)$
