Answer
See image:
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Work Step by Step
Divide the equation with $144$
$\displaystyle \frac{x^{2}}{16}-\frac{y^{2}}{9}=1$
When in this form, the hyperbola has
foci on the x-axis: $\quad \displaystyle \frac{x^{2}}{a^{2}}-\frac{y^{2}}{b^{2}}=1\quad a=4, \ b=3$
Center-to-focus distance: $\quad c=\sqrt{a^{2}+b^{2}}=\sqrt{16+9}=5$
Foci: $\quad (\pm c, 0)=\quad (\pm 5, 0)$
Vertices: $\quad (\pm a, 0)=\quad (\pm 4, 0)$
Asymptotes: $\quad y=\displaystyle \pm\frac{b}{a}x=\pm\frac{3}{4}x$
$y=\displaystyle \pm\frac{3}{4}x$
