Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 11: Parametric Equations and Polar Coordinates - Section 11.6 - Conic Sections - Exercises 11.6 - Page 678: 32

Answer

See image: .

Work Step by Step

Divide the equation with $3$ $\displaystyle \frac{y^{2}}{3}-\frac{x^{2}}{1}=1,\ \quad$ We recognize the standard equation of a hyperbola. Foci on the y-axis: $\quad \displaystyle \frac{y^{2}}{a^{2}}-\frac{x^{2}}{b^{2}}=1\quad \Rightarrow a=\sqrt{3},\ b=1$ Center-to-focus distance: $\quad c=\sqrt{a^{2}+b^{2}}=\sqrt{3+1}=2$ Foci: $\quad (0, \pm c)= \quad (0, \pm 2)$ Vertices: $\quad (0, \pm\sqrt{3})$ Asymptotes: $\quad y=\displaystyle \pm\frac{a}{b}x=\pm\frac{\sqrt{3}}{1}x=\pm x$ $y=\pm\sqrt{3}x$
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