Chapter 11: Parametric Equations and Polar Coordinates - Section 11.6 - Conic Sections - Exercises 11.6 - Page 678: 10

Focus: $(0,\displaystyle \frac{3}{2})\quad$ Directrix: $y=-\displaystyle \frac{3}{2}$

$x^{2}=4py\quad \Rightarrow \quad $the parabola opens up, $x^{2}=6y $ $x^{2}=6\displaystyle \cdot\frac{4}{4}\cdot y $ $x^{2}=4(\displaystyle \frac{3}{2})y \quad \Rightarrow \quad p=\frac{3}{2}$ Focus: $(0,\displaystyle \frac{3}{2})\quad$ Directrix: $y=-\displaystyle \frac{3}{2}$