Answer
See image:

Work Step by Step
Divide the equation with $90$
$\displaystyle \frac{x^{2}}{10}+\frac{y^{2}}{9}=1$
$\displaystyle \frac{x^{2}}{(\sqrt{10})^{2}}+\frac{y^{2}}{(3)^{2}}=1$, which is of the form $\quad \displaystyle \frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1 \quad (a\gt b)$,
$\Rightarrow$ the foci are on the x-axis.
Center-to-focus distance: $\quad c=\sqrt{a^{2}-b^{2}}=\sqrt{10-9}=1$
Foci: $\quad(\pm c, 0)= \quad(\pm 1, 0)$
Vertices: $\quad (\pm a, 0)= \quad (\pm\sqrt{10}, 0)$