Answer
See image:
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Work Step by Step
Divide the equation with $16$
$\displaystyle \frac{x^{2}}{2}-\frac{y^{2}}{8}=1$
When in this form, the hyperbola has foci on the x-axis: $\quad \displaystyle \frac{x^{2}}{a^{2}}-\frac{y^{2}}{b^{2}}=1\quad a=\sqrt{2}, \ b=2\sqrt{2}$
Center-to-focus distance: $\quad c=\sqrt{a^{2}+b^{2}}=\sqrt{2+8}=\sqrt{10}$
Foci: $\quad (\pm c, 0)=\quad (\pm\sqrt{10}, 0)$
Vertices: $\quad (\pm a, 0)=\quad (0,\ \pm\sqrt{2} )$
Asymptotes: $\quad y=\displaystyle \pm\frac{b}{a}x=\pm\frac{2\sqrt{2}}{\sqrt{2}}x$
$y=\pm 2x$
