Chapter 11: Parametric Equations and Polar Coordinates - Section 11.6 - Conic Sections - Exercises 11.6 - Page 678: 14

Focus: $(0,-\displaystyle \frac{1}{32})\quad$ Directrix: $y=\displaystyle \frac{1}{32}$ .

$y=-8x^{2}$ $x^{2}=-\displaystyle \frac{1}{8}y,\qquad $opens down, $x^{2}=-4py$ $x^{2}=-4(\displaystyle \frac{1}{32})y \quad \Rightarrow \quad p=\frac{1}{32}$ Focus: $(0,-\displaystyle \frac{1}{32})\quad$ Directrix: $y=\displaystyle \frac{1}{32}$