Answer
See image:
Work Step by Step
Divide the equation with 400
$\displaystyle \frac{x^{2}}{25}+\frac{y^{2}}{16}=1$
$\displaystyle \frac{x^{2}}{5^{5}}+\frac{y^{2}}{4^{2}}=1$, which is of the form $\quad \displaystyle \frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1 \quad (a\gt b)$,
$\Rightarrow$ the foci are on the x-axis.
Center-to-focus distance: $\quad c=\sqrt{a^{2}-b^{2}}=\sqrt{25-16}=3$
Foci: $\quad(\pm c, 0)= \quad(\pm 3, 0)$
Vertices: $\quad (\pm a, 0)= \quad (\pm 5, 0)$
