Chapter 11: Parametric Equations and Polar Coordinates - Section 11.6 - Conic Sections - Exercises 11.6 - Page 678: 11

Focus: $(0,-2)\quad$ Directrix: $y=2$ .

$x^{2}=-4py$ Thus the parabola opens down, $x^{2}=-8y $ $x^{2}=-8\displaystyle \cdot\frac{4}{4}\cdot y $ $x^{2}=-4(2)y \quad \Rightarrow \quad p=2$ Focus: $(0,-2)\quad$ Directrix: $y=2$