Answer
See image:
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Work Step by Step
Divide the equation with $2$
$\displaystyle \frac{x^{2}}{1}+\frac{y^{2}}{2}=1$
$\displaystyle \frac{x^{2}}{1^{2}}+\frac{y^{2}}{(\sqrt{2})^{2}}=1$, which is of the form $\quad \displaystyle \frac{x^{2}}{b^{2}}+\frac{y^{2}}{a^{2}}=1 \quad (a\gt b)$
$\Rightarrow$ the foci are on the y-axis.
Center-to-focus distance: $\quad c=\sqrt{a^{2}-b^{2}}=\sqrt{2-1}=1$
Foci: $\quad(0, \pm c)= \quad(0, \pm 1)$
Vertices: $\quad (0, \pm a)= \quad (0, \pm\sqrt{2})$
