Answer
$f'(x)=9x^{2}+10x+6$
$f"(x)=18x+10$
$f^{(3)}(x)=18$
Work Step by Step
$f(x)=3x^{3}+5x^{2}+6x$
$f'(x)=3(3)x^{3-1}+5(2)x^{2-1}+6x^{1-1}$
$f'(x)=9x^{2}+10x^{1}+6x^{0}$
$f'(x)=9x^{2}+10x+6$
$f"(x)=9(2)x^{2-1}+10x^{1-1}+0$
$f"(x)=18x^{1}+10x^{0}$
$f"(x)=18x+10$
$f^{(3)}(x)=18x^{1-1}+0$
$f^{(3)}(x)=18x^{0}$
$f^{(3)}(x)=18$
