Answer
$g'(x)=1$
Work Step by Step
Simplify the expression:
$g(x)=\dfrac{x^2-1}{x-1}=\dfrac{(x+1)(x-1)}{x-1}=x+1$
Apply ´power rule:
$g'(x)=1$
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 3 - Derivatives - 3.3 Rules of Differentiation - 3.3 Exercises - Page 151: 31
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