#### Answer

$g'(w) = 10w^{11}$

#### Work Step by Step

$g(w) = \frac{5}{6}w^{12}$
$g'(w) = \frac{5}{6} \times (w^{12})'$
$(w^{12})'=12w^{11}$
Therefore
$g'(w) = \frac{5}{6} \times (w^{12})'= \frac{5}{6} \times 12w^{11} = 10w^{11}$

Published by
Pearson

ISBN 10:
0321947347

ISBN 13:
978-0-32194-734-5

$g'(w) = 10w^{11}$

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