#### Answer

$g'(t) =\frac{3}{\sqrt t}$

#### Work Step by Step

$g(t) = 6\sqrt t$
$g'(t) = 8\times (\sqrt t)'$
$(\sqrt t)'=(t^{0.5})'= 0.5t^{-0.5}=\frac{1}{2t^{0.5}}=\frac{1}{2\sqrt t}$
Therefore
$g'(t) = 6 \times (\sqrt t)'= 6\times \frac{1}{2\sqrt t}= \frac{3}{\sqrt t}$