Answer
$s'(t)=2t^{-1/2}-t^{3}+1$
Work Step by Step
$s(t)=4\sqrt t-(1/4)t^{4}+t+1$
$s(t)=4t^{1/2}-(1/4)t^{4}+t+1$
$s'(t)=(4)(1/2)t^{1/2-1}-(1/4)(4)t^{4-1}+1t^{1-1}+0$
$s'(t)=2t^{-1/2}-1t^{3}+1t^{0}$
$s'(t)=2t^{-1/2}-t^{3}+1$
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 3 - Derivatives - 3.3 Rules of Differentiation - 3.3 Exercises - Page 151: 24
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