Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 3 - Derivatives - 3.3 Rules of Differentiation - 3.3 Exercises: 24

Answer

$s'(t)=2t^{-1/2}-t^{3}+1$

Work Step by Step

$s(t)=4\sqrt t-(1/4)t^{4}+t+1$ $s(t)=4t^{1/2}-(1/4)t^{4}+t+1$ $s'(t)=(4)(1/2)t^{1/2-1}-(1/4)(4)t^{4-1}+1t^{1-1}+0$ $s'(t)=2t^{-1/2}-1t^{3}+1t^{0}$ $s'(t)=2t^{-1/2}-t^{3}+1$
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