Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 3 - Derivatives - 3.3 Rules of Differentiation - 3.3 Exercises: 18

Answer

$f'(s)=\dfrac{1}{8\sqrt{s}}$

Work Step by Step

Rewrite the function: $f(s)=\dfrac{1}{4}s^{1/2}$ Apply the power rule: $f'(s) =\dfrac{1}{4}(\dfrac{1}{2})s^{1/2-1}$ $f'(s)=\dfrac{1}{8}s^{-1/2}$ $f'(s)=\dfrac{1}{8\sqrt{s}}$
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