Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 3 - Derivatives - 3.3 Rules of Differentiation - 3.3 Exercises - Page 151: 21


$f'(x) = 40x^3-32$

Work Step by Step

$f(x) = 10x^4-32x+e^2$ Using Power rule: $f'(x) = 10(4)x^{4-1}-32(1)x^{1-1}+(0)e^2x^{0-1} = 40x^3-32$
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