Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 3 - Derivatives - 3.3 Rules of Differentiation - 3.3 Exercises: 29

Answer

$f'(w)=2w$

Work Step by Step

Simplify the expression: $f(w)=\dfrac{w^3-w}{w}$ $f(w)=\dfrac{w^3}{w}-\dfrac{w}{w}=w^2-1$ Apply power rule: $f'(w)=2w$
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