Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 3 - Derivatives - 3.3 Rules of Differentiation - 3.3 Exercises - Page 151: 22



Work Step by Step

$f(t)$=$6\sqrt t - 4t^{3}+9$ $f(t)=6t^{1/2}- 4t^{3}+9$ $f(t)=6(1/2)t^{1/2-1}- 4(3)t^{3-1}+0$ $f(t)=3t^{-1/2}- 12t^{2}$
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