## Calculus: Early Transcendentals (2nd Edition)

$g'(w) = 6w^2+4w+10$
$g(w)=2w^3+2w^2+10w$ Using Power Rule: $g'(w) =2(3)w^{3-1}+2(2)w^{2-1}+10(1)w^{1-1}= 6w^2+4w+10$