Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 3 - Derivatives - 3.3 Rules of Differentiation - 3.3 Exercises - Page 151: 23


$g'(w) = 6w^2+4w+10$

Work Step by Step

$g(w)=2w^3+2w^2+10w$ Using Power Rule: $g'(w) =2(3)w^{3-1}+2(2)w^{2-1}+10(1)w^{1-1}= 6w^2+4w+10$
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