Answer
$g'(t) = 200t$
Work Step by Step
$g(t) =100t^2$
$g'(t) = 100\times (t^2)'$
$(t^2)'=2t^1 = 2t$
Therefore
$g'(t) = 100 \times (t^2)'= 100\times 2t = 200t$
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 3 - Derivatives - 3.3 Rules of Differentiation - 3.3 Exercises - Page 151: 17
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