$g'(t) = 200t$
Work Step by Step
$g(t) =100t^2$ $g'(t) = 100\times (t^2)'$ $(t^2)'=2t^1 = 2t$ Therefore $g'(t) = 100 \times (t^2)'= 100\times 2t = 200t$
You can help us out by revising, improving and updating this answer.Update this answer
After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.