Answer
$\frac{1}{150} (10t-7)^{15} +c.$
Work Step by Step
We have
$$
\int (10t-7)^{14} d t= \frac{1}{10}\int 10 (10t-7)^{14} d t\\
= \frac{1}{10} \frac{1}{15} (10t-7)^{15} +c\\
= \frac{1}{150} (10t-7)^{15} +c.
$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 5 - The Integral - Chapter Review Exercises - Page 278: 53
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