Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - Chapter Review Exercises - Page 278: 53


$\frac{1}{150} (10t-7)^{15} +c.$

Work Step by Step

We have $$ \int (10t-7)^{14} d t= \frac{1}{10}\int 10 (10t-7)^{14} d t\\ = \frac{1}{10} \frac{1}{15} (10t-7)^{15} +c\\ = \frac{1}{150} (10t-7)^{15} +c. $$
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