Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - Chapter Review Exercises - Page 278: 45


$$ \frac{4}{5}x^5 -3x^4 + 3x^3+c$$

Work Step by Step

\begin{align*} \int\left(2 x^{2}-3 x\right)^{2} d x&= \int\left(4 x^{4}-12 x^3 +9x^2\right) d x\\ &= \frac{4}{5}x^5 -3x^4 + 3x^3+c \end{align*}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.