Answer
$-\cos (\theta-8) +c $
Work Step by Step
Let $ u=\theta-8$, then $ du=d\theta $ and hence $$\int \sin(\theta-8) d\theta=\int \sin u du=-\cos u +c= -\cos (\theta-8) +c $$
Where we used the fact that the integral of sine is negative cosine.
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 5 - The Integral - Chapter Review Exercises - Page 278: 19
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