Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - Chapter Review Exercises - Page 278: 22



Work Step by Step

We have $$\int (9t^{-2/3}+4t^{7/3})dt =\frac{9}{1/3}t^{1/3}+\frac{4}{10/3}t^{10/3}+c=27t^{1/3}+\frac{6}{5}t^{10/3}+c.$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.