Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - Chapter Review Exercises - Page 278: 48



Work Step by Step

\begin{align*} \int_1^3r^{-4}dr&= \frac{-1}{3} r^{-3}\bigg|_1^3\\ &=\frac{1}{3}\left(1-\frac{1}{27}\right)\\ &= \frac{26}{81} \end{align*}
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