Answer
$$\frac{26}{81}$$
Work Step by Step
\begin{align*}
\int_1^3r^{-4}dr&= \frac{-1}{3} r^{-3}\bigg|_1^3\\
&=\frac{1}{3}\left(1-\frac{1}{27}\right)\\
&= \frac{26}{81}
\end{align*}
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 5 - The Integral - Chapter Review Exercises - Page 278: 48
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
