Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - Chapter Review Exercises - Page 278: 52



Work Step by Step

\begin{aligned} \int_{0}^{2}(t-[t])^{2} d t & \\ &=\int_{0}^{1} t^{2} d t+\int_{1}^{2}(t-1)^{2} d t \\ &=\left.\frac{1}{3} t^{3}\right|_{0} ^{1}+\left.\frac{1}{3}(t-1)^{3}\right|_{1} ^{2} \\ &=\frac{1}{3}+\frac{1}{3}=\frac{2}{3} \end{aligned}
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