Answer
$$4x^5 - \frac{9}{4}x^4-x^2+c$$
Work Step by Step
\begin{align*}
\int\left(20 x^{4}-9 x^{3}-2 x\right) d x&= 20\times \frac{1}{5}x^5- 9\times \frac{1}{4}x^4 -x^2+c\\
&= 4x^5 - \frac{9}{4}x^4-x^2+c
\end{align*}
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 5 - The Integral - Chapter Review Exercises - Page 278: 43
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