Answer
$$\int (y+2)^4dy = \frac{1}{5}(y+2)^5+c.$$
Work Step by Step
Let $ u=y+2$, then $ du=dy $ and hence we have
$$\int (y+2)^4dy =\in u^4fu =\frac{1}{5}u^5+c= \frac{1}{5}(y+2)^5+c $$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 5 - The Integral - Chapter Review Exercises - Page 278: 25
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