Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - Chapter Review Exercises - Page 278: 49



Work Step by Step

\begin{align*} \int_{-3}^{3} | x^2-4|dx& = \int_{-3}^{2}( x^2-4)dx-\int_{2}^{3}( x^2-4)dx\\ &= \frac{x^{3}}{3}-\left.4 x\right|_{-3} ^{2}+4 x-\left.\frac{x^{3}}{3}\right|_{2} ^{3} \\ &= \frac{46}{3} \end{align*}
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