Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - Chapter Review Exercises - Page 278: 34


$$y= \tan x +1 $$

Work Step by Step

Given$$ \frac{d y}{d x}=\sec^2 x, \quad y(\pi/4)=2$$ Since :\begin{align*} y&= \int (\sec^2 x) dx\\ &= \tan x +c \end{align*} at $x=\pi/4,\ \ \ y= 2 $, then $c= 1$, hence $$y= \tan x +1 $$
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