Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - Chapter Review Exercises - Page 278: 47


$$ \frac{1}{4}x^4+x^3+c$$

Work Step by Step

\begin{align*} \int \frac{x^5+ 3x^4}{x^2}dx&= \int (x^3+ 3x^2)dx\\ &= \frac{1}{4}x^4+x^3+c \end{align*}
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