Answer
$$ - \infty $$
Work Step by Step
$$\eqalign{
& \mathop {\lim }\limits_{x \to {0^ + }} \left( {\frac{{10}}{x} - \frac{3}{{{x^2}}}} \right) \cr
& {\text{Evaluate the limit}} \cr
& \mathop {\lim }\limits_{x \to {0^ + }} \left( {\frac{{10}}{x} - \frac{3}{{{x^2}}}} \right) = \infty - \infty \cr
& {\text{Simplify}} \cr
& \mathop {\lim }\limits_{x \to {0^ + }} \left( {\frac{{10}}{x} - \frac{3}{{{x^2}}}} \right) = \mathop {\lim }\limits_{x \to {0^ + }} \left( {\frac{{10x - 3}}{{{x^2}}}} \right) \cr
& = \mathop {\lim }\limits_{x \to {0^ + }} \left( {\frac{{10x - 3}}{{{x^2}}}} \right) \cr
& {\text{Evaluate the limit}} \cr
& = \frac{{10\left( 0 \right) - 3}}{{{{\left( 0 \right)}^2}}} = \frac{{ - 3}}{0} = - \infty \cr} $$
