Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.7 Exercises - Page 564: 17

Answer

$\dfrac {11}{4}$

Work Step by Step

$\lim _{x\rightarrow 1}\dfrac {x^{11}-1}{x^{4}-1}=\dfrac {\dfrac {d}{dx}\left( x^{11}-1\right) }{\dfrac {d}{dx}\left( x^{4}-1\right) }=\dfrac {11x^{10}}{4x^{3}}=\dfrac {11}{4}x^{7}=\dfrac {11}{4}\times 1^{7}=\dfrac {11}{4}$
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