Answer
$0$
Work Step by Step
$\lim _{x\rightarrow \infty }\dfrac {5x+3}{x^{3}-6x+2}=\dfrac {\dfrac {d}{dx}\left( 5x+3\right) }{\dfrac {d}{dx}\left( x^{3}-6x+2\right) }=\dfrac {5}{3x^{2}-6}=\dfrac {5}{\infty }=0$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.7 Exercises - Page 564: 24
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