Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.7 Exercises - Page 564: 2

Answer

\[ - 1\]

Work Step by Step

\[\begin{gathered} \mathop {\lim }\limits_{x \to 0} \frac{{1 - {e^x}}}{x} \hfill \\ {\text{Evaluate }}f\left( x \right){\text{ for the given values and complete the table}}{\text{.}} \hfill \\ x = - 0.1 \to f\left( { - 0.1} \right) = \frac{{1 - {e^{ - 0.1}}}}{{ - 0.1}} \approx - 0.9516 \hfill \\ x = - 0.01 \to f\left( { - 0.01} \right) = \frac{{1 - {e^{ - 0.01}}}}{{ - 0.01}} \approx - 0.9950 \hfill \\ x = - 0.001 \to f\left( { - 0.001} \right) = \frac{{1 - {e^{ - 0.001}}}}{{ - 0.001}} \approx - 0.9995 \hfill \\ x = 0.001 \to f\left( {0.001} \right) = \frac{{1 - {e^{0.001}}}}{{0.001}} \approx - 1.0005 \hfill \\ x = 0.01 \to f\left( {0.01} \right) = \frac{{1 - {e^{0.01}}}}{{0.01}} \approx - 1.0050 \hfill \\ x = 0.1 \to f\left( {0.1} \right) = \frac{{1 - {e^{0.1}}}}{{0.1}} \approx - 1.0517 \hfill \\ \boxed{\begin{array}{*{20}{c}} x&{f\left( x \right)} \\ { - 0.1}&{ - 0.9516} \\ { - 0.01}&{ - 0.9950} \\ { - 0.001}&{ - 0.9995} \\ {0.001}&{ - 1.0005} \\ {0.01}&{ - 1.0050} \\ {0.1}&{ - 1.0517} \end{array}} \hfill \\ {\text{Therefore,}} \hfill \\ \mathop {\lim }\limits_{x \to 0} \frac{{1 - {e^x}}}{x} \approx - 1 \hfill \\ {\text{Graph}} \hfill \\ \end{gathered} \]
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