Answer
$\dfrac {a}{b}$
Work Step by Step
$\lim _{x\rightarrow 0}\dfrac {\sin ax}{\sin bx}=\dfrac {\dfrac {d}{dx}\sin ax}{\dfrac {d}{dx}\sin bx}=\dfrac {a\times \cos ax}{b\times \cos bx}=\dfrac {a\times \cos 0}{b\times\cos 0}=\dfrac {a}{b}$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.7 Exercises - Page 564: 20
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